[文件操作] [已解决]批处理如何将文件名中以指定字符分割成的两部分字符串/字段调换位置

@echo off
setlocal enabledelayedexpansion
for /f "delims=" %%i in ('dir /b /s /a-d ^| findstr "\-[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]"') do (
    set "s1=%%~ni"
    set "s1=!s1:~-8!"
    set "s2=%%~ni"
    set "s2=!s2:~0,-9!"
    ren "%%i" "!s1!-!s2!%%~xi"
)
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@echo off
setlocal enabledelayedexpansion
for /f "delims=" %%i in ('dir /b /a-d ^| findstr "\-[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]"') do (
    set "s1=%%~ni"
    set "s1=!s1:~-8!"
    set "s2=%%~ni"
    set "s2=!s2:~0,-9!"
    ren "%%i" "!s1!-!s2!%%~xi"
)
for /f "delims=" %%i in ('dir /b /ad ^| findstr "\-[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]"') do (
    set "s1=%%i"
    set "s1=!s1:~-8!"
    set "s2=%%i"
    set "s2=!s2:~0,-9!"
    ren "%%i" "!s1!-!s2!"
)
复制代码