[数值计算] 【已解决】用批处理找出1000以下的自然数中，属于 3 或 5 的倍数的数字之和

@echo off
(for /l %%a in (3,1,999) do (
    set "n="
    set /a "1/(%%a%%3)"||set n=1
    set /a "1/(%%a%%5)"||set n=1
    if defined n set /a s+=%%a
))>nul 2>&1
echo;%s%
pause
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@echo off
set/p n=Please input a number:
set/a "n3=(n-1)/3, n5=(n-1)/5, n15=(n-1)/15, S=(3*n3*(n3+1)+5*n5*(n5+1)-15*n15*(n15+1))>>0x01"&call set/p  =Result=:%%S%%
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'&@(cls&cscript -nologo -e:vbscript "%~0"&PAUSE&EXIT)
num=0
for i = 1 to 1000-1
if i mod 3 = 0 or i mod 5 = 0 then
      num=num+i
    wscript.echo i
end if
next
wscript.echo "总和:"&num
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'&@(cls&cscript -nologo -e:vbscript "%~0"&PAUSE&EXIT)
num=0
num1=0
num2=0
do until num1 >= 1000-1
    num1=num1+3
    wscript.echo num1
    num=num+num1
loop
do until num2 >= 1000-5
    num2=num2+5
if num2 mod 3 <> 0 then '不枚举是3倍数的
    wscript.echo num2
    num=num+num2
end if
loop
wscript.echo "总和:"&num
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