[转载]CMD获取当前光标坐标、位置

523066680

偶然看到的一个问答

Yay! I had given up hope of ever getting a pure batch solution. Nicely done.

get-cursor-position-via-windows-10-console-vt-100-escape-sequence

@echo off
for /F "delims=#" %%a in ('"prompt #$E# & for %%a in (1) do rem"') do set "ESC=%%a"

call :get_cursor_pos
exit /b

:get_cursor_pos
set "response="
set pos=2

:_get_loop
REM *** Request Cursor position
<nul set /p "=%ESC%[6n" 
FOR /L %%# in (1 1 %pos%) DO pause < CON > NUL

for /F "tokens=1 skip=1 eol=" %%C in ('"REPLACE /W ? . < con"') DO (
    set "char=%%C"
)
set "response=%response%%char%"
set /a pos+=1
if "%char%" NEQ "R" goto :_get_loop

set response
exit /b
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其他参考：
https://www.dostips.com/forum/viewtopic.php?t=9454

CrLf

牛逼，竟然还能用Escape屏幕控制码。但为什么 <nul set /p "=%ESC%[6n" 能将内容回填到StdIn？

更多玩法自己摸索：
https://blog.csdn.net/lano2088/article/details/51985563

a20150604

微软对 终端 的支持从 WIN10 某版本开始, 仍在持续升级中

https://docs.microsoft.com/en-us ... -terminal-sequences

https://devblogs.microsoft.com/c ... y/windows-terminal/

EnableVTMode 应用例:
在 WIN10 控制台显示一个变色甜甜圈(甜甜圈代码 为 转载, 我加了 WIN10 终端开启代码, 变色), Dev-C++ 5.11 编译测试

#include <stdbool.h>
#include <windows.h>
#include <stdint.h>
#include <stdio.h>

#include <math.h>

#ifndef ENABLE_VIRTUAL_TERMINAL_PROCESSING
#define ENABLE_VIRTUAL_TERMINAL_PROCESSING 0x0004
#endif

#ifndef ENABLE_VIRTUAL_TERMINAL_INPUT
#define ENABLE_VIRTUAL_TERMINAL_INPUT 0x0200
#endif

#ifndef DISABLE_NEWLINE_AUTO_RETURN
#define DISABLE_NEWLINE_AUTO_RETURN 0x0008
#endif

#define ESC "\x1b"
#define CSI "\x1b["

#define R(mul,shift,x,y) \
    _=x; \
    x -= mul*y>>shift; \
    y += mul*_>>shift; \
    _ = 3145728-x*x-y*y>>11; \
    x = x*_>>10; \
    y = y*_>>10;

int8_t b[1760], z[1760];
char c[1760][100];

bool EnableVTMode();

void HSV2RGB_int(int h, int s, int v, int* r, int* g, int* b);

int main() {

	//First, enable VT mode
	bool fSuccess = EnableVTMode();
	if (!fSuccess) {
		printf("Unable to enter VT processing mode. Quitting.\n");
		return -1;
	}
	HANDLE hOut = GetStdHandle(STD_OUTPUT_HANDLE);
	if (hOut == INVALID_HANDLE_VALUE) {
		printf("Couldn't get the console handle. Quitting.\n");
		return -1;
	}

	// <nul set /p "=%_ESC%[?25l" & REM _ESC [ ? 25 l    DECTCEM    Text Cursor Enable Mode Hide    Hide the cursor
	printf("\x1b[?25l");    //  Text Cursor Enable Mode Hide    Hide the cursor

	char scr_buff[1760 * 100 + 1], str1[2], str[20];
	str1[1] = '\0';
	strcpy(scr_buff, "");

	int sA = 1024, cA = 0, sB = 1024, cB = 0, _;
	int i, j, k;
	int t;

	int h, s, v, r, g, bb;
	h = 120, s = 100;
	for (;;) {
		h += 1; h %= 360;
		strcpy(scr_buff, "\x1b[1;1H");

		memset(b, 32, 1760);  // text buffer
		memset(c, 0, 1760 * 100);  // text buffer

		for (i = 0; i < 1760; i++) c[i][0] = ' ';

		memset(z, 127, 1760);   // z buffer
		int sj = 0, cj = 1024;
		for (j = 0; j < 90; j++) {
			int si = 0, ci = 1024;  // sine and cosine of angle i
			for (i = 0; i < 324; i++) {
				int R1 = 1, R2 = 2048, K2 = 5120 * 1024;

				int x0 = R1 * cj + R2,
					x1 = ci * x0 >> 10,
					x2 = cA * sj >> 10,
					x3 = si * x0 >> 10,
					x4 = R1 * x2 - (sA * x3 >> 10),
					x5 = sA * sj >> 10,
					x6 = K2 + R1 * 1024 * x5 + cA * x3,
					x7 = cj * si >> 10,
					x = 40 + 30 * (cB * x1 - sB * x4) / x6,
					y = 12 + 15 * (cB * x4 + sB * x1) / x6,
					N = (-cA * x7 - cB * ((-sA * x7 >> 10) + x2) - ci * (cj * sB >> 10) >> 10) - x5 >> 7;

				int o = x + 80 * y;
				int8_t zz = (x6 - K2) >> 15;
				if (22 > y && y > 0 && x > 0 && 80 > x && zz < z[o]) {
					z[o] = zz;

					t = N > 0 ? N : 0;

					v = t << 3; // << 3 <--> * 8 <--> * 100 / 12;
					HSV2RGB_int(h, s, v, &r, &g, &bb);

					sprintf(c[o], " [48;2;%d;%d;%dm ", r, g, bb);   // 21=255/12
					c[o][0] = '\x1b';

					strcat(c[o], "\x1b[48;2;0;0;0m");
				}
				R(5, 8, ci, si)  // rotate i
			}
			R(9, 7, cj, sj)  // rotate j
		}
		for (k = 0; 1761 > k; k++) {
			strcat(scr_buff, (k % 80 ? (c[k]) : "\n"));  // putchar(k % 80 ? b[k] : 10);
		}

		R(5, 7, cA, sA);
		R(5, 8, cB, sB);
		usleep(1000);

		printf("%s", scr_buff);
	}
}

// h: [0,360]; s: [0,100]; v:[0,100]; r,g,b:[0,255]
void HSV2RGB_int(int h, int s, int v, int* r, int* g, int* b) {

	const int zoom = 100;
	h = h < 0 ? h % 360 + 360 : (h >= 360 ? h % 360 : h);
	s = s < 0 ? 0 : (s > zoom ? zoom : s);
	v = v < 0 ? 0 : (v > zoom ? zoom : v);

	int r1, g1, b1;
	int c = round(1.0 * v * s / zoom);
	int h_ = h % 360 / 60;

	int u = (zoom * h / 60) % (zoom * 2) - zoom * 1;

	int t = u >> 31;
	int x = round(1.0 * c * (zoom * 1 - ((t & (-u)) | (~t & u))) / zoom);
	int m = v - c;
	switch (h_) {
	case 0:
		r1 = c, g1 = x, b1 = 0;
		break;
	case 1:
		r1 = x, g1 = c, b1 = 0;
		break;
	case 2:
		r1 = 0, g1 = c, b1 = x;
		break;
	case 3:
		r1 = 0, g1 = x, b1 = c;
		break;
	case 4:
		r1 = x, g1 = 0, b1 = c;
		break;
	case 5:
		r1 = c, g1 = 0, b1 = x;
		break;
	}

	*r = round((r1 + m) * 255.0 / zoom); *g = round((g1 + m) * 255.0 / zoom); *b = round((b1 + m) * 255.0 / zoom);
}

bool EnableVTMode() {
	// Set output mode to handle virtual terminal sequences
	HANDLE hOut = GetStdHandle(STD_OUTPUT_HANDLE);
	if (hOut == INVALID_HANDLE_VALUE) {
		return 0;
	}

	DWORD dwMode = 0;
	if (!GetConsoleMode(hOut, &dwMode)) {
		return 0;
	}

	dwMode |= ENABLE_VIRTUAL_TERMINAL_PROCESSING;
	if (!SetConsoleMode(hOut, dwMode)) {
		return 0;
	}
	return 1;
}
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netbenton

小提速，同可时也可以用来获取最大的行，列值。

@echo off&setlocal enabledelayedexpansion

::文本只能保存为ansi编码，其它编码可能出错。
::Win 10 下测试通过。

for /F "tokens=1 delims=#" %%a in ('"prompt #$E# & echo on & for %%b in (1) do rem"') do set "ESC=%%a"

set/p=%ESC%[255;255H<nul

for /l %%b in (2,1,7) do (
if "!K!" neq "R" (
set /p=%ESC%[6n<nul
(for /l %%a in (1,1,%%b) do pause>nul
for /f "tokens=2 delims=键" %%c in ('"xcopy /w . 2>nul"') do set K=%%c
set str=!str!!k!
)<con
)
)

set /p in=当前窗口显示最大行；列：!str!，回车退出
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