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标题: [文件操作] [已解决]求助批处理怎样把多条命令的返回结果输出到文本不换行？ [打印本页]

作者: habulu 时间: 2015-3-1 00:19 标题: [已解决]求助批处理怎样把多条命令的返回结果输出到文本不换行？

本帖最后由 pcl_test 于 2017-3-31 17:42 编辑

比如这两个命令（命令可能不同）

wmic datafile where "drive='c:' and path='\\Windows\\' and filename='notepad'" get filename,size | find "notepad" >c:\1.txt
wmic datafile where "drive='c:' and path='\\Windows\\' and filename='notepad'" get filename,size | find "notepad" >>c:\1.txt
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想让他们不换行，用下面的命令，可是没输出

@echo off  
for /f "tokens=*" %%i in ('wmic datafile where "drive='c:' and path='\\Windows\\' and filename='notepad'" get filename,size | find "notepad"') do ((set/p="%%i"<nul)>>"c:\1.txt")
pause
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请教有没什么办法让多条命令的输出不换行

作者: pcl_test 时间: 2015-3-1 11:30

回复 1# habulu
两个例子参考下

@echo off
for /f "delims=" %%i in ('echo 125 ^&^& ver ^&^& echo 345') do set /p=%%i<nul
pause
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@echo off
setlocal enabledelayedexpansion
set s=
for /f "tokens=1-2" %%i in ('wmic datafile where "drive='c:' and path='\\Windows\\' and filename='notepad'" get filename^,size ^| find "notepad" ^&^& wmic datafile where "drive='c:' and path='\\Windows\\' and filename='regedit'" get filename^,size ^| find "regedit"') do set "s=!s!%%i %%j "
>1.txt echo !s!
pause
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作者: habulu 时间: 2015-3-1 20:59

可以了非常感谢

欢迎光临批处理之家 (http://bathome.net./)