[文本处理] 如何获取nslookup命令返回结果中的IPv6地址？

recoba

请问  想用nslookup 指定DNS(74.82.42.42)    批处理A文件获得ipv6地址       生成B文件
nslookup -qt=AAAA www.google.com 74.82.42.42
像这样


A文件  www.google.com
获得
B文件  2607:f8b0:4007:807::200e    www.google.com

这个批处理要怎么写啊？

ivor

@echo off&setlocal ENABLEDELAYEDEXPANSION
(for /f "delims=" %%i in (a.txt) do (
	for /f "tokens=1,2" %%j in ('nslookup -qt^=AAAA %%i 74.82.42.42') do (
		set last=%%k
	)
	echo !last! %%i 
))>b.txt
pause
复制代码

回复 1# recoba

codegay

"""
python获取DNS查询结果.py
http://bbs.bathome.net/thread-39978-1-1.html
2016年4月9日 10:08:16 codegay
"""
import re
import subprocess
host="www.google.com"
txt=subprocess.getoutput("nslookup -qt=AAAA www.google.com 223.5.5.5")

print(txt)

result=re.findall(r"""Address:  ((?:\w*:){5}\w*)""",txt)[0]

print("匹配结果:",result)

with open("result.txt","w+") as f:
    f.write(result+"\t"+host+"\n")

"""
非权威应答:

服务器:  public1.alidns.com
Address:  223.5.5.5

名称:    www.google.com
Address:  2404:6800:4005:801::2004

匹配结果: 2404:6800:4005:801::2004
[Finished in 0.2s]
"""
复制代码

recoba

感谢  好心人真多啊