[文件操作] 批处理如何实现提取文件名中指定位数的数字来重命名文件？

foreveriuu

目录下大量的文件，文件名格式类似
我的文件1_12345678.zip
我的文件2_22342345.doc
34232345_又一个文件.chm

需要提取8位数字将文件更名，后缀不变
12345678.zip
22342345.doc
34232345.chm

GNU

@echo off
setlocal enabledelayedexpansion
for /f "delims=" %%i in ('dir /b /a-d ^| findstr "[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]"') do (
    for /f %%j in ('echo "%%~nxi" ^| grep -Po "\d{8}"') do (
        set "NewName=%%j%%~xi" 
    )
    ren "%%i" "!NewName!"
)
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foreveriuu

多谢楼上，grep是第三方命令，有没有不用第三方命令的办法呢？

pcl_test

第三方可用ren2
ren2 -f ".*(\d{8}).*(\..*)" "$1$2"

小程936

考虑到set /a会自动忽略非数字，可用
set a=&set /a a=b
if "%a%" == "%b%" echo %b%是数字

/zhqsystem/zhq

水一个

@echo off&(color 0e&chcp 936&setlocal enabledelayedexpansion)2>nul
for /f "delims=" %%i in ('dir/a-d/s/b/l/on ".\*.*"')do if /i not "%%~fi"=="%~f0" (
 set "name_="%%~ni""&&set "name=!name_:_=";"!"
 for %%j in (!name!)do (set "n=%%j"&set "num="
  for /l %%n in (0,1,8192)do if /i not "!n:~%%n,1!"=="" (
   for /l %%o in (0,1,9)do if /i "!n:~%%n,1!"=="%%o" set/a "num+=1"
  )
  if !num! gtr 7 ren "%%~fi" "%%~j%%~xi"
 )
)
pause
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WHY

PowerShell -c "dir *[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]*.*|ren -newName{$_.Name -replace '.*?(\d{8}).*(\..+)$','$1$2'}"
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ttszuo

借用2楼的代码

@echo off
cd /d "%~dp0"
for /f "delims=" %%i in ('dir /b /a-d ^| findstr "[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]"') do (
    for /f "tokens=1,2 delims=^_" %%a in ('echo.%%~ni') do (
        echo.%%a|findstr /be "[0-9]*" >nul && move "%%~nxi" "%%a%%~xi"|| move "%%~nxi" "%%b%%~xi"
    )
)
pause
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也可以这个

@echo off
cd /d "%~dp0"
for /f "delims=" %%i in ('dir /b /a-d ^| findstr "[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]"') do (
    for /f "tokens=1,2 delims=^_" %%a in ('echo.%%~ni') do (
        if 1%%a gtr 99999999 (move "%%~nxi" "%%a%%~xi")  else (move "%%~nxi" "%%b%%~xi")
    )
)
pause
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借用5楼的判断是否是数字

@echo off
setlocal enabledelayedexpansion
cd /d "%~dp0"
for /f "delims=" %%i in ('dir /b /a-d ^| findstr "[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]"') do (
    for /f "tokens=1,2 delims=^_" %%a in ('echo.%%~ni') do (
            set /a num=%%a
           if "!num!"=="%%a" (move "%%~nxi" "%%a%%~xi")  else (move "%%~nxi" "%%b%%~xi")
    )
)
pause
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foreveriuu

楼上的脚本可用，非常感谢，我用python写了个脚本

import os, os.path, re

ress = re.compile('\d{8}')

# 批量改名
def batchrename(root):
    for parent,dirnames,filenames in os.walk(root):
        for name in filenames:
            if len(re.findall(ress, name))>0:
                ss=re.findall(ress, name)[0]
                print(os.path.join(parent, ss+name[name.rfind('.'):]))
                os.rename(os.path.join(parent, name), os.path.join(parent, ss+name[name.rfind('.'):]))

if __name__ == '__main__':      
    batchrename('.')
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hzf1019

楼上各位大大好厉害，菜鸟学习了~~

pcl_test

//&cls&(dir /a-d/b |findstr "[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]")|cscript -nologo -e:jscript "%~f0"&pause&exit
while(!WScript.StdIn.AtEndOfStream){
    var f = (new ActiveXObject('Scripting.Filesystemobject')).GetFile(WScript.StdIn.ReadLine());
    var newname = f.Name.replace(/.*?(\d{8}).*(\.[^\.]+)$/, '$1$2');
    try{f.Name = newname}catch(e){}
}
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